By Alfred S. Posamentier, Gordon Sheridan

Math Motivators! a chain of enrichment investigations in secondary arithmetic, is made from 4 books. They contain investigations in pre-algebra, algebra, geometry, and enterprise and patron arithmetic. each one ebook comprises nearly 32 black-line masters that may be reproduced for pupil use. The investigations probe a large spectrum of mathematical thoughts and purposes at numerous degrees.

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How many points are determined if exactly two of the lines are parallel? 12. How many lines may be drawn between four points lying in a plane if no three of the points are on the same straight line? 13. What is the total number of angles formed by two intersecting transversals cutting two parallel lines? 6. Three Parallel Lines Cut by Two Transversals. Theorem 15 may be applied to prove an important property regarding the segments of two transversals intercepted by three parallel lines; namely, THEOREM 16.

Find the hypotenuse c of a right triangle ,whose legs are given as indicated. Use the formula c = Va 2 + b2• (a) a =6",b =8". (d) a = 21",b =45". (b) a = 10", b = 24". , b = v'ls in. (c) a = 9"', b = 12". /2 in. 7. One leg and the aypotenuse c of a right triangle are given as indicated. Use the formula b = V c2 - a2 to find the length of the other leg. (a) c = 17", a = 15". (d) c = 34", a = 16". (e) c = 100", a = 60". (b) c = 25", a = 24". (c) c = 35", a = 21". , a = 2Vs in. 8. Find the area of each of the right triangles whose sides are given as follows.

3. Parallels Perpendicular to the SaDle Line. THEOREM 8. Two lines in the saDle plane perpendiculn to the S8Dle line are parallel. GIVEN: The two lines II and 12 lying in the same plane and perpendicular to the line l3 at the points A and B, respectively. To PROVE: ll"~. · * This method of proof makes use of the fact that only one of two conclusions is possible. Arguments arising from the use of one conclusion show a violation of an established fact - a definition, proposition, axiom, or postulate - and hence prove that this conclusion is invalid.